Series-Parallel Circuits

Learning Objectives
  • Identify series-parallel combinations in complex circuits
  • Apply systematic reduction techniques for equivalent resistance
  • Analyze circuits with both series and parallel elements
  • Use step-by-step simplification strategies

What are Series-Parallel Circuits?

Most real-world circuits contain both series and parallel combinations. These circuits require systematic analysis techniques to simplify and solve.

Series-Parallel Circuit Example

+ R₁ R₂ R₃ R₄ Series Parallel Series

R₁ and R₄ in series with a parallel combination of R₂ and R₃

Systematic Analysis Strategy

💡 Step-by-Step Approach
  1. Identify combinations: Find all series and parallel groupings
  2. Start from the far end: Simplify the circuit from the load toward the source
  3. Replace components: Calculate equivalent resistance for each group
  4. Repeat: Continue until you have a single equivalent resistance
  5. Work backward: Find voltages and currents in individual components

Step 1: Identify Parallel Combination

R₂ and R₃ are in parallel. Calculate their equivalent:

Parallel R₂ || R₃ R_parallel = (R₂ × R₃) / (R₂ + R₃)

Step 2: Combine with Series Resistors

Now the parallel combination is in series with R₁ and R₄:

Total Resistance R_total = R₁ + R_parallel + R₄

Series-Parallel Circuit Calculator

Circuit Parameters

24 V
10 Ω
30 Ω
30 Ω
10 Ω

Results

R_parallel (R₂||R₃)
15 Ω
R_total
35 Ω
Total Current
0.69 A
V across R₂||R₃
10.3 V
I through R₂
0.34 A
I through R₃
0.34 A

Practice Problem

Calculate Total Resistance and Current

Given: V = 12V, R₁ = 100Ω, R₂ = 100Ω (parallel), R₃ = 100Ω (parallel), R₄ = 100Ω

Show Solution

Step 1: Parallel combination of R₂ and R₃

R_parallel = (100 × 100) / (100 + 100)
R_parallel = 10000 / 200 = 50Ω

Step 2: Total resistance

R_total = R₁ + R_parallel + R₄
R_total = 100 + 50 + 100 = 250Ω

Step 3: Total current

I_total = V / R_total
I_total = 12V / 250Ω = 0.048A = 48mA

Answer: R_total = 250Ω, I_total = 48mA

Summary

  • Series-Parallel: Combines both series and parallel elements
  • Strategy: Simplify from far end toward source
  • Parallel first: Often easier to combine parallel groups first
  • Work backward: Use equivalent circuits to find branch values
  • KVL/KCL: Still apply to any simplified section